把這個(gè)地址的程序 中,山消這一句山唯老public void print(){
新林網(wǎng)站建設(shè)公司創(chuàng)新互聯(lián),新林網(wǎng)站設(shè)計(jì)制作,有大型網(wǎng)站制作公司豐富經(jīng)驗(yàn)。已為新林超過(guò)千家提供企業(yè)網(wǎng)站建設(shè)服務(wù)。企業(yè)網(wǎng)站搭建\成都外貿(mào)網(wǎng)站制作要多少錢(qián),請(qǐng)找那個(gè)售后服務(wù)好的新林做網(wǎng)站的公司定做!
改成public void print(){}加一個(gè)大逗升括號(hào)就可以運(yùn)行了。
題目好像是讓你做個(gè)增強(qiáng)版的List ,簡(jiǎn)單的都實(shí)現(xiàn)了 程序架子大概是這樣,排序查找什么的百度搜下 算法很多,套著每樣寫(xiě)個(gè)方法就行了,測(cè)試就在main‘方法里寫(xiě)
public?class?MyList?{
private?String[]?arr;
private?int?count?;
public?MyList?(int?count){
arr?=?new?String[count];
知雹塵???????this.count?=?count;
}
public?MyList?(int[]?intArr){
arr?=?new?String[intArr.length];
this.count?=?intArr.length;
for(int?i=0;iintArr.length;i++){
arr[i]?=?intArr[i]+"";
}
}
public?MyList?(String[]?stringArr){
arr?=?stringArr;
this.count?=?stringArr.length;
}
public?int?getLength(){
return?count;
}
//清空容器內(nèi)肆卜的數(shù)組。
public?void?clearAll(){
arr?=?new?String[count];
}
//通過(guò)給定元素下標(biāo)來(lái)刪除某一元素
public?void?removeBySeqn(int?seqn){
搭禪???????if(seqn?=?0??seqncount){
arr[seqn]?=?null;
}
}
public?static?void?main(String[]?args){
MyList??list?=?new?MyList?(40);
MyList??list1?=?new?MyList?({3,2,125,56,123});
MyList??list2?=?new?MyList?({"123",""ad});
list2.removeBySeqn(0);
list1.clearAll();
}
}
《Java遺傳算法編程》百度網(wǎng)盤(pán)pdf最新全集下載:
鏈接:
?pwd=xv3v 提取碼: xv3v
簡(jiǎn)介:本書(shū)簡(jiǎn)單、直接地介紹了遺傳算法,并且針對(duì)所討論的示例問(wèn)題,給出了模襲搏Java代碼的算法實(shí)現(xiàn)禪薯。全書(shū)分為6章。第1章簡(jiǎn)單介紹了人工智能和生物進(jìn)化的知識(shí)背景,這也是遺傳算法的歷史知識(shí)背景。第2章給出了一個(gè)基本遺傳算法的實(shí)現(xiàn);第4章和第5章,分別針對(duì)機(jī)器人控制器、旅行商問(wèn)題、排課問(wèn)題展開(kāi)分析和討論,并給出了算法實(shí)現(xiàn)。在這些章的末尾,還給出旦祥了一些練習(xí)供讀者深入學(xué)習(xí)和實(shí)踐。第6章專(zhuān)門(mén)討論了各種算法的優(yōu)化問(wèn)題。 ?
通過(guò)遺傳算法走迷宮。雖然圖1和圖2均成功走出迷宮,但是圖1比圖2的路徑長(zhǎng)的多,且復(fù)雜,遺傳算法可以計(jì)算出有多少種可能性,并選擇其中最簡(jiǎn)潔的作為運(yùn)算結(jié)果。
示例圖1:
示凱陪例圖2:
實(shí)現(xiàn)代碼:
import?java.util.ArrayList;
import?java.util.Collections;
import?java.util.Iterator;
import?java.util.LinkedList;
import?java.util.List;
import?java.util.Random;
/**
* 用遺傳算法走迷宮
*
* @author Orisun
*
*/
public?class?GA {
int?gene_len;?// 基因長(zhǎng)度
int?chrom_len;?// 染色體長(zhǎng)度
int?population;?// 種群磨孫嫌大小
double?cross_ratio;?// 交叉率
double?muta_ratio;?// 變異率
int?iter_limit;?// 最多進(jìn)化的代數(shù)
Listboolean[] individuals;?// 存儲(chǔ)當(dāng)代種群的染色體
Labyrinth labyrinth;
int?width;??????//迷宮一行有多少個(gè)格子
int?height;?????//迷宮有多少行
public?class?BI {
double?fitness;
boolean[] indv;
public?BI(double?f,?boolean[] ind) {
fitness = f;
indv = ind;
}
public?double?getFitness() {
return?fitness;
}
public?boolean[] getIndv() {
return?indv;
}
}
ListBI best_individual;?// 存儲(chǔ)每一代中最優(yōu)秀的個(gè)體
public?GA(Labyrinth labyrinth) {
this.labyrinth=labyrinth;
this.width = labyrinth.map[0].length;
this.height = labyrinth.map.length;
chrom_len =?4?* (width+height);
gene_len =?2;
population =?20;
cross_ratio =?0.83;
muta_ratio =?0.002;
iter_limit =?300;
individuals =?new?ArrayListboolean[](population);
best_individual =?new?ArrayListBI(iter_limit);
}
public?int?getWidth() {
return?width;
}
public?void?setWidth(int?width) {
this.width = width;
}
public?double?getCross_ratio() {
return?cross_ratio;
}
public?List瞎手BI getBest_individual() {
return?best_individual;
}
public?Labyrinth getLabyrinth() {
return?labyrinth;
}
public?void?setLabyrinth(Labyrinth labyrinth) {
this.labyrinth = labyrinth;
}
public?void?setChrom_len(int?chrom_len) {
this.chrom_len = chrom_len;
}
public?void?setPopulation(int?population) {
this.population = population;
}
public?void?setCross_ratio(double?cross_ratio) {
this.cross_ratio = cross_ratio;
}
public?void?setMuta_ratio(double?muta_ratio) {
this.muta_ratio = muta_ratio;
}
public?void?setIter_limit(int?iter_limit) {
this.iter_limit = iter_limit;
}
// 初始化種群
public?void?initPopulation() {
Random r =?new?Random(System.currentTimeMillis());
for?(int?i =?0; i population; i++) {
int?len = gene_len * chrom_len;
boolean[] ind =?new?boolean[len];
for?(int?j =?0; j len; j++)
ind[j] = r.nextBoolean();
individuals.add(ind);
}
}
// 交叉
public?void?cross(boolean[] arr1,?boolean[] arr2) {
Random r =?new?Random(System.currentTimeMillis());
int?length = arr1.length;
int?slice =?0;
do?{
slice = r.nextInt(length);
}?while?(slice ==?0);
if?(slice length /?2) {
for?(int?i =?0; i slice; i++) {
boolean?tmp = arr1[i];
arr1[i] = arr2[i];
arr2[i] = tmp;
}
}?else?{
for?(int?i = slice; i length; i++) {
boolean?tmp = arr1[i];
arr1[i] = arr2[i];
arr2[i] = tmp;
}
}
}
// 變異
public?void?mutation(boolean[] individual) {
int?length = individual.length;
Random r =?new?Random(System.currentTimeMillis());
individual[r.nextInt(length)] ^=?false;
}
// 輪盤(pán)法選擇下一代,并返回當(dāng)代最高的適應(yīng)度值
public?double?selection() {
boolean[][] next_generation =?new?boolean[population][];?// 下一代
int?length = gene_len * chrom_len;
for?(int?i =?0; i population; i++)
next_generation[i] =?new?boolean[length];
double[] cumulation =?new?double[population];
int?best_index =?0;
double?max_fitness = getFitness(individuals.get(best_index));
cumulation[0] = max_fitness;
for?(int?i =?1; i population; i++) {
double?fit = getFitness(individuals.get(i));
cumulation[i] = cumulation[i -?1] + fit;
// 尋找當(dāng)代的最優(yōu)個(gè)體
if?(fit max_fitness) {
best_index = i;
max_fitness = fit;
}
}
Random rand =?new?Random(System.currentTimeMillis());
for?(int?i =?0; i population; i++)
next_generation[i] = individuals.get(findByHalf(cumulation,
rand.nextDouble() * cumulation[population -?1]));
// 把當(dāng)代的最優(yōu)個(gè)體及其適應(yīng)度放到best_individual中
BI bi =?new?BI(max_fitness, individuals.get(best_index));
// printPath(individuals.get(best_index));
//System.out.println(max_fitness);
best_individual.add(bi);
// 新一代作為當(dāng)前代
for?(int?i =?0; i population; i++)
individuals.set(i, next_generation[i]);
return?max_fitness;
}
// 折半查找
public?int?findByHalf(double[] arr,?double?find) {
if?(find ?0?|| find ==?0?|| find arr[arr.length -?1])
return?-1;
int?min =?0;
int?max = arr.length -?1;
int?medium = min;
do?{
if?(medium == (min + max) /?2)
break;
medium = (min + max) /?2;
if?(arr[medium] find)
min = medium;
else?if?(arr[medium] find)
max = medium;
else
return?medium;
}?while?(min max);
return?max;
}
// 計(jì)算適應(yīng)度
public?double?getFitness(boolean[] individual) {
int?length = individual.length;
// 記錄當(dāng)前的位置,入口點(diǎn)是(1,0)
int?x =?1;
int?y =?0;
// 根據(jù)染色體中基因的指導(dǎo)向前走
for?(int?i =?0; i length; i++) {
boolean?b1 = individual[i];
boolean?b2 = individual[++i];
// 00向左走
if?(b1 ==?false? b2 ==?false) {
if?(x ?0? labyrinth.map[y][x -?1] ==?true) {
x--;
}
}
// 01向右走
else?if?(b1 ==?false? b2 ==?true) {
if?(x +?1? width labyrinth.map[y][x +?1] ==?true) {
x++;
}
}
// 10向上走
else?if?(b1 ==?true? b2 ==?false) {
if?(y ?0? labyrinth.map[y -?1][x] ==?true) {
y--;
}
}
// 11向下走
else?if?(b1 ==?true? b2 ==?true) {
if?(y +?1? height labyrinth.map[y +?1][x] ==?true) {
y++;
}
}
}
int?n = Math.abs(x - labyrinth.x_end) + Math.abs(y -labyrinth.y_end) +?1;
//????? if(n==1)
//????????? printPath(individual);
return?1.0?/ n;
}
// 運(yùn)行遺傳算法
public?boolean?run() {
// 初始化種群
initPopulation();
Random rand =?new?Random(System.currentTimeMillis());
boolean?success =?false;
while?(iter_limit-- ?0) {
// 打亂種群的順序
Collections.shuffle(individuals);
for?(int?i =?0; i population -?1; i +=?2) {
// 交叉
if?(rand.nextDouble() cross_ratio) {
cross(individuals.get(i), individuals.get(i +?1));
}
// 變異
if?(rand.nextDouble() muta_ratio) {
mutation(individuals.get(i));
}
}
// 種群更替
if?(selection() ==?1) {
success =?true;
break;
}
}
return?success;
}
//? public static void main(String[] args) {
//????? GA ga = new GA(8, 8);
//????? if (!ga.run()) {
//????????? System.out.println("沒(méi)有找到走出迷宮的路徑.");
//????? } else {
//????????? int gen = ga.best_individual.size();
//????????? boolean[] individual = ga.best_individual.get(gen - 1).indv;
//????????? System.out.println(ga.getPath(individual));
//????? }
//? }
// 根據(jù)染色體打印走法
public?String getPath(boolean[] individual) {
int?length = individual.length;
int?x =?1;
int?y =?0;
LinkedListString stack=new?LinkedListString();
for?(int?i =?0; i length; i++) {
boolean?b1 = individual[i];
boolean?b2 = individual[++i];
if?(b1 ==?false? b2 ==?false) {
if?(x ?0? labyrinth.map[y][x -?1] ==?true) {
x--;
if(!stack.isEmpty() stack.peek()=="右")
stack.poll();
else
stack.push("左");
}
}?else?if?(b1 ==?false? b2 ==?true) {
if?(x +?1? width labyrinth.map[y][x +?1] ==?true) {
x++;
if(!stack.isEmpty() stack.peek()=="左")
stack.poll();
else
stack.push("右");
}
}?else?if?(b1 ==?true? b2 ==?false) {
if?(y ?0? labyrinth.map[y -?1][x] ==?true) {
y--;
if(!stack.isEmpty() stack.peek()=="下")
stack.poll();
else
stack.push("上");
}
}?else?if?(b1 ==?true? b2 ==?true) {
if?(y +?1? height labyrinth.map[y +?1][x] ==?true) {
y++;
if(!stack.isEmpty() stack.peek()=="上")
stack.poll();
else
stack.push("下");
}
}
}
StringBuilder sb=new?StringBuilder(length/4);
IteratorString iter=stack.descendingIterator();
while(iter.hasNext())
sb.append(iter.next());
return?sb.toString();
}
}
新聞標(biāo)題:遺傳算法java源代碼 遺傳算法java源代碼是什么
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