這篇文章將為大家詳細(xì)講解有關(guān)SQL刪除重復(fù)數(shù)據(jù)的方法,小編覺得挺實(shí)用的,因此分享給大家做個(gè)參考,希望大家閱讀完這篇文章后可以有所收獲。
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在sql中,可以使用select語句刪除重復(fù)數(shù)據(jù),語法為:“select * from 字段 where 字段id in (select 字段id from 字段 group by 字段 having count(字段id) > 1)”。
本教程操作環(huán)境:windows7系統(tǒng)、MySQL8.0版本、Dell G3電腦。
用SQL語句,刪除掉重復(fù)項(xiàng)只保留一條
在幾千條記錄里,存在著些相同的記錄,如何能用SQL語句,刪除掉重復(fù)的呢
查找表中多余的重復(fù)記錄,重復(fù)記錄是根據(jù)單個(gè)字段(peopleId)來判斷
select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
擴(kuò)展:
刪除表中多余的重復(fù)記錄,重復(fù)記錄是根據(jù)單個(gè)字段(peopleId)來判斷,只留有rowid最小的記錄
delete from people where peopleName in (select peopleName from people group by peopleName having count(peopleName) > 1) and peopleId not in (select min(peopleId) from people group by peopleName having count(peopleName)>1)
查找表中多余的重復(fù)記錄(多個(gè)字段)
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
刪除表中多余的重復(fù)記錄(多個(gè)字段),只留有rowid最小的記錄
delete from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
查找表中多余的重復(fù)記錄(多個(gè)字段),不包含rowid最小的記錄
select * from vitae a where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
消除一個(gè)字段的左邊的第一位:
update tableName set [Title]=Right([Title],(len([Title])-1)) where Title like '村%'
消除一個(gè)字段的右邊的第一位:
update tableName set [Title]=left([Title],(len([Title])-1)) where Title like '%村'
假刪除表中多余的重復(fù)記錄(多個(gè)字段),不包含rowid最小的記錄
update vitae set ispass=-1where peopleId in (select peopleId from vitae group by peopleId
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名稱欄目:SQL刪除重復(fù)數(shù)據(jù)的方法
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